Little programing

Who can help me with a little program in C++?
>>>>>
Este dat un sir de caractere.De aflat de cite ori este intilnit fiecare din caractere.


well .. its only for those who know romanian:)
i'm w8ing for an replay .. or w/e .

Romanian to english translation of the problem:
You get a string of characters...print how many times you find each character of that string.

I don't know how the C++ code would look like...but you can try to declare an array of 128 positions (array={0,0,0,..,0}) that could contain the first 128 characters from ASCII.
You could read letter by letter until end of line/end of file character and if any character is found, you could increment that position.(if you find character 'a' that has the ASCII code 97 according to [You must be registered and logged in to see this link.] , you could do array[97]++ so your array would become like this: array={0,..0,1,0,..,0}, where 1 is located on the 97th position of that array.
At the end you could check from 0 to 128 if there are characters found (value of array in their position to be different that 0), and print "this character has been found this number of times".

Hope this helps...

Sorry for the offtopic , but ... Flow ! Get your fluffy buttox back here at least for a while...

tnx flow .... did it already
i was at the Laboratory .. when i posted this,and i didn't have any ideea how to start

this is how it would look ... with some mistakes
#include<string.h>
#include<conio.h>
#include<stdio.h>
void main (void){
char s[256], x[53]="AaBbCcDdEeFfGgHhIiJjKkLlMmNnOoPpQqRrSsTtUuVvWwXxYyZz"; int i,j,n,m,k;
puts("introduceti sirul: ");
gets(s);
n=strlen(x);
m=strlen(s);
for(i=0; i<n; i++)
{ k=0;
for (j=0; j<m; j++)
{ if (x[i]==s[j]) k++;} if (k==0)continue; else {printf("%c=%d",x[i],k); printf("\n"); } }
getch();
}
btw ... this is first and the easyest one ....